Math Solution Trigonometry

Solution: Find the values of x, where 0 ≤ x ≤ 360, such that 2sin^2 x + 5cosx + 1 = 0

Find the values of x, where 0 ≤ x ≤ 360, such that 2sin^2 x + 5cosx + 1 = 0. Determine the value of x, given the range and the equation.

Find the values of x, where 0 ≤ x ≤ 360, such that 2sin^2 x + 5cosx + 1 = 0.

Problem Statement:

Find the values of x, where 0 ≤ x ≤ 360, such that 2sin2x + 5cosx + 1 = 0.

Problem Answer:

x = 120° or 240°

Solution:

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